A list of species having the formula of `XZ_(4)` is given below `XeF_(4), SF_(4), SiF_(4), BF_(4)^(-), BrF_(4)^(-), [Cu(NH_(3))4]^(2+),[FeCl_(4)]^(2-), [CoCl_(4)]^(2-)` and `[PtCl_(4)]^(2-)`
Defining shape on the basis of the location of `X` and `Z` atoms, the total number of species having a square planar shape is

Answer

To determine the total number of species having a square planar shape from the given list of compounds with the formula `XZ₄`, we will analyze each species one by one based on their hybridization and molecular geometry.

### Step-by-Step Solution:

1. **Identify the Species**: The given species are:
- XeF₄
- SF₄
- SiF₄
- BF₄⁻
- BrF₄⁻
- [Cu(NH₃)₄]²⁺
- [FeCl₄]²⁻
- [CoCl₄]²⁻
- [PtCl₄]²⁻

2. **Analyze Each Species**:
- **XeF₄**:
- Valence electrons: 8 (Xe) + 4 (F) = 12
- Hybridization: \( \frac{12}{2} = 6 \) → sp³d²
- Shape: Square planar (4 F atoms in equatorial positions, 2 lone pairs in axial positions).

- **SF₄**:
- Valence electrons: 6 (S) + 4 (F) = 10
- Hybridization: \( \frac{10}{2} = 5 \) → sp³d
- Shape: Seesaw (not square planar).

- **SiF₄**:
- Valence electrons: 4 (Si) + 4 (F) = 8
- Hybridization: \( \frac{8}{2} = 4 \) → sp³
- Shape: Tetrahedral (not square planar).

- **BF₄⁻**:
- Valence electrons: 3 (B) + 4 (F) + 1 (charge) = 8
- Hybridization: \( \frac{8}{2} = 4 \) → sp³
- Shape: Tetrahedral (not square planar).

- **BrF₄⁻**:
- Valence electrons: 7 (Br) + 4 (F) + 1 (charge) = 12
- Hybridization: \( \frac{12}{2} = 6 \) → sp³d²
- Shape: Square planar (4 F atoms in equatorial positions, 2 lone pairs in axial positions).

- **[Cu(NH₃)₄]²⁺**:
- Oxidation state of Cu: +2 → 4s² 3d⁹
- Hybridization: dsp² (due to strong field ligands).
- Shape: Square planar.

- **[FeCl₄]²⁻**:
- Oxidation state of Fe: +2 → 4s² 3d⁶
- Hybridization: sp³ (due to weak field ligands).
- Shape: Tetrahedral (not square planar).

- **[CoCl₄]²⁻**:
- Oxidation state of Co: +2 → 4s² 3d⁷
- Hybridization: sp³ (due to weak field ligands).
- Shape: Tetrahedral (not square planar).

- **[PtCl₄]²⁻**:
- Oxidation state of Pt: +2 → 6s² 5d⁸
- Hybridization: dsp² (due to strong field ligands).
- Shape: Square planar.

3. **Count Square Planar Species**:
- From the analysis, the species that exhibit a square planar shape are:
- XeF₄
- BrF₄⁻
- [Cu(NH₃)₄]²⁺
- [PtCl₄]²⁻

Thus, the total number of species with a square planar shape is **4**.

### Final Answer:
The total number of species having a square planar shape is **4**.