What are 'X' and 'Y' respectively?

Options

A.
B.
C. cases
D.

Answer

To solve the question, we need to identify the compounds 'X' and 'Y' formed from the reaction of the given reactant with two different reagents.

### Step-by-Step Solution:

1. **Identify the Reactant**: The reactant given is CH=CHCHO, which is an aldehyde with a vinyl group (alkene) attached to it.

2. **Reagent 1 - NaBH4**: The first reagent is NaBH4 (sodium borohydride), which is known for selectively reducing aldehydes and ketones to their corresponding alcohols.
- When CH=CHCHO reacts with NaBH4, the aldehyde group (CHO) will be reduced to an alcohol (CH2OH).
- The alkene (C=C) remains unchanged.
- Therefore, the product formed (let's denote it as 'X') is CH2=CH-CH2OH (an allylic alcohol).

3. **Reagent 2 - H2/Pd**: The second reagent is H2 in the presence of palladium (Pd), which can reduce both aldehydes and alkenes.
- When CH=CHCHO reacts with H2/Pd, both the aldehyde and the alkene will be reduced.
- The aldehyde (CHO) is reduced to CH2OH, and the alkene (C=C) is reduced to a saturated alkane (C-C).
- Therefore, the product formed (let's denote it as 'Y') is CH2-CH2-CH2OH (a saturated alcohol).

4. **Conclusion**:
- 'X' is the product from the reaction with NaBH4: CH2=CH-CH2OH.
- 'Y' is the product from the reaction with H2/Pd: CH2-CH2-CH2OH.

### Final Answer:
- 'X' = CH2=CH-CH2OH (an allylic alcohol)
- 'Y' = CH2-CH2-CH2OH (a saturated alcohol)