The reaction of propene with `HOCI (CI_(2)+H_(2)O)` proceeds through the intermediate:

Options

A. `CH_(3)-CHCl-CH_(2)^(+)`
B. `CH_(3)-CH^(+)-CH_(2)-OH`
C. `CH_(3)-CH^(+)-CH_(2)-Cl`
D. `CH_(3)-CH(OH)-CH_(2)^(+)`

Answer

To determine the intermediate formed in the reaction of propene with HOCl, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactant is propene, which has the structure CH₃-CH=CH₂.

2. **Understanding HOCl**:
- HOCl can dissociate into OH⁻ (hydroxide ion) and Cl⁺ (chloronium ion). The chlorine atom in HOCl acts as an electrophile due to its positive charge.

3. **Electrophilic Attack**:
- The Cl⁺ ion can attack the double bond in propene. The double bond has electron density, making it a site for electrophilic attack.
- The attack can occur at either of the two carbon atoms involved in the double bond.

4. **Formation of Carbocation**:
- If Cl⁺ attacks the first carbon (C1), the positive charge will be on the second carbon (C2), forming a primary carbocation: CH₃-CH(Cl)-CH₂⁺.
- If Cl⁺ attacks the second carbon (C2), the positive charge will be on the first carbon (C1), forming a secondary carbocation: CH₂⁺-CH-CH₃.

5. **Stability of Carbocations**:
- Secondary carbocations are more stable than primary carbocations due to hyperconjugation and inductive effects. Therefore, the attack at C2 leading to a secondary carbocation is preferred.

6. **Formation of the Intermediate**:
- The stable secondary carbocation formed is CH₂⁺-CH-CH₃ (with Cl attached to C2). This carbocation is the intermediate in the reaction.

7. **Final Product Formation**:
- The hydroxide ion (OH⁻) can then attack the carbocation to form the final product, which is CH₃-CH(Cl)-CH₂OH.

### Conclusion:
The intermediate formed in the reaction of propene with HOCl is a secondary carbocation.