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The number of bond pairs is X and lone p...

The number of bond pairs is X and lone pairs is Y on Xe (central atom) in `XeO_(3)F_(2)`. What is the sum of `X+Y`?

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To solve the problem of finding the sum of bond pairs (X) and lone pairs (Y) on the central atom (xenon) in the compound \(XeO_3F_2\), we can follow these steps: ### Step 1: Determine the Valence Electrons of Xenon Xenon (Xe) is a noble gas and has 8 valence electrons in its outer shell. ### Step 2: Identify the Bonds Formed In \(XeO_3F_2\): - Xenon forms **2 single bonds** with the two fluorine (F) atoms. - Xenon forms **3 double bonds** with the three oxygen (O) atoms. ### Step 3: Calculate Electrons Used in Bonding - Each single bond with fluorine uses **1 electron** from xenon. Therefore, 2 electrons are used for the two F atoms. - Each double bond with oxygen uses **2 electrons** from xenon. Therefore, 6 electrons are used for the three O atoms (3 double bonds). ### Step 4: Total Electrons Used in Bonding - Total electrons used = Electrons used for F + Electrons used for O - Total = 2 (for F) + 6 (for O) = **8 electrons**. ### Step 5: Determine Lone Pairs Since all 8 valence electrons of xenon are used for bonding, there are **0 electrons left** for lone pairs. - Therefore, the number of lone pairs (Y) = **0**. ### Step 6: Calculate Bond Pairs The total number of bond pairs (X) is calculated as follows: - 2 bond pairs from the two F atoms (single bonds). - 3 bond pairs from the three O atoms (double bonds). - Total bond pairs = 2 (from F) + 3 (from O) = **5**. ### Step 7: Find the Sum of X and Y Now, we can find the sum: - \(X + Y = 5 + 0 = 5\). ### Final Answer The sum of bond pairs (X) and lone pairs (Y) on the central atom in \(XeO_3F_2\) is **5**. ---
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