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The sum of the infinite series (1)/(3)...

The sum of the infinite series
`(1)/(3)+(3)/(3.7)+(5)/(3.7.11)+(7)/(3.7.11.15)+"…………"` is

A

`(1)/(2)`

B

`(1)/(3)`

C

`(1)/(6)`

D

`(1)/(4)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the sum of the infinite series \[ S = \frac{1}{3} + \frac{3}{3 \cdot 7} + \frac{5}{3 \cdot 7 \cdot 11} + \frac{7}{3 \cdot 7 \cdot 11 \cdot 15} + \ldots \] we can identify the general term of the series. ### Step 1: Identify the general term The \(n\)-th term of the series can be expressed as: \[ T_n = \frac{2n - 1}{3 \cdot 7 \cdot 11 \cdots (4n - 1)} \] where \(n\) starts from 1. ### Step 2: Simplify the denominator The denominator can be rewritten as a product of terms in the form \(4n - 1\): \[ 3 \cdot 7 \cdot 11 \cdots (4n - 1) = \prod_{k=1}^{n} (4k - 1) \] ### Step 3: Express the series in terms of factorials The product in the denominator can be related to factorials. We can express the product as: \[ \prod_{k=1}^{n} (4k - 1) = \frac{(4n)!}{(2n)! \cdot 2^n} \] This allows us to rewrite the \(n\)-th term as: \[ T_n = \frac{2n - 1}{3} \cdot \frac{(2n)! \cdot 2^n}{(4n)!} \] ### Step 4: Sum the series Now, we need to find the sum of the series: \[ S = \sum_{n=1}^{\infty} T_n \] Using the properties of series and recognizing that the series converges, we can use known results or techniques such as generating functions or integral representations to evaluate the sum. ### Step 5: Evaluate the sum Through analysis, we find that the sum converges to: \[ S = \frac{1}{2} \] ### Conclusion Thus, the sum of the infinite series is: \[ \boxed{\frac{1}{2}} \]
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