A certain reaction occurs in two steps as
(I) `2SO_(2(g))+2NO_(2(g)) to 2SO_(3(g))+2NO_((g))`
`(ii) 2NO_((g) ) +O_(2) (g) to 2NO_(2(g))`
In the reaction ,______.

Options

A. `NO_(2(g))` in intermediate
B. `NO_((g))` intermediate
C. `NO_((g))` is catalyst
D. `O_(2(g))` is intermediate

Answer

To solve the question regarding the reaction that occurs in two steps, we will analyze each step and identify the intermediate formed during the process.

### Step 1: Write down the reactions

1. **First Reaction:**
\[ 2SO_2(g) + 2NO_2(g) \rightarrow 2SO_3(g) + 2NO(g) \]

2. **Second Reaction:**
\[ 2NO(g) + O_2(g) \rightarrow 2NO_2(g) \]

### Step 2: Identify the species formed and consumed

- In the **first reaction**, we see that nitrogen monoxide (NO) is produced as a product.
- In the **second reaction**, nitrogen monoxide (NO) is consumed as a reactant.

### Step 3: Determine the role of NO

Since NO is produced in the first reaction and then consumed in the second reaction, it does not appear in the overall reaction as a reactant or a product. This means that NO is an intermediate in this reaction sequence.

### Step 4: Conclusion

Based on the analysis, we can conclude that NO is an intermediate in the overall reaction process.

### Final Answer

In the reaction, NO acts as an intermediate.

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