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The solubility product values of barium ...

The solubility product values of barium sulphate and barium carbonate are `1.0xx10^(-10)` and `5.0xx10^(-9)` respectively when the two salts are simultaneously equilibrated in pure water the ratio of `([SO_(4)^(2-)])/([CO_(3)^(2-)])` is

A

0.02

B

`0.10`

C

0.05

D

0.12

Text Solution

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The correct Answer is:
To solve the problem, we need to find the ratio of the concentrations of sulfate ions \([SO_4^{2-}]\) to carbonate ions \([CO_3^{2-}]\) when barium sulfate \((BaSO_4)\) and barium carbonate \((BaCO_3)\) are in equilibrium in pure water. ### Step-by-Step Solution: 1. **Write the Dissociation Equations:** - For barium sulfate: \[ BaSO_4 (s) \rightleftharpoons Ba^{2+} (aq) + SO_4^{2-} (aq) \] - For barium carbonate: \[ BaCO_3 (s) \rightleftharpoons Ba^{2+} (aq) + CO_3^{2-} (aq) \] 2. **Define the Solubility Products:** - The solubility product \(K_{sp}\) for barium sulfate is given by: \[ K_{sp1} = [Ba^{2+}][SO_4^{2-}] = S_1 \cdot S_1 = S_1^2 \] - The solubility product \(K_{sp}\) for barium carbonate is given by: \[ K_{sp2} = [Ba^{2+}][CO_3^{2-}] = S_2 \cdot S_2 = S_2^2 \] 3. **Express the Concentrations:** - Let \(S_1\) be the solubility of barium sulfate and \(S_2\) be the solubility of barium carbonate. - The total concentration of barium ions from both salts is: \[ [Ba^{2+}] = S_1 + S_2 \] 4. **Set Up the Equations:** - From the solubility products, we can write: \[ K_{sp1} = (S_1 + S_2) \cdot S_1 \] \[ K_{sp2} = (S_1 + S_2) \cdot S_2 \] 5. **Divide the Two Equations:** - Dividing \(K_{sp1}\) by \(K_{sp2}\): \[ \frac{K_{sp1}}{K_{sp2}} = \frac{(S_1 + S_2) \cdot S_1}{(S_1 + S_2) \cdot S_2} \] - This simplifies to: \[ \frac{K_{sp1}}{K_{sp2}} = \frac{S_1}{S_2} \] 6. **Substitute the Given Values:** - Given \(K_{sp1} = 1.0 \times 10^{-10}\) and \(K_{sp2} = 5.0 \times 10^{-9}\): \[ \frac{S_1}{S_2} = \frac{1.0 \times 10^{-10}}{5.0 \times 10^{-9}} = \frac{1}{50} = 0.02 \] 7. **Conclusion:** - Therefore, the ratio of \([SO_4^{2-}]\) to \([CO_3^{2-}]\) is: \[ \frac{[SO_4^{2-}]}{[CO_3^{2-}]} = 0.02 \] ### Final Answer: The ratio of \([SO_4^{2-}]/[CO_3^{2-}]\) is **0.02**.
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