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How many of the following reagents react...

How many of the following reagents react with arene diazonium slats to form aryl halides?
i. `HBF_(4)//Delta`
ii. `KHS`
iii. `CuCN//KCN`
iv. `CuBr//HBr`
v. `Cu//HCl`
vi. `KI//Delta`
vii. `CH_(3)CH_(2)OH`
viii. `H_(3)PO_(2)//H_(2)O`

Text Solution

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To determine how many of the given reagents react with arene diazonium salts to form aryl halides, we will analyze each reagent one by one. ### Step-by-Step Solution: 1. **Reagent i: HBF₄ / Δ (Heat)** - When arene diazonium salt reacts with HBF₄ and heat, it replaces the diazonium group (N₂) with a fluorine atom (F). - **Product:** Aryl fluoride (Fluorobenzene). - **Conclusion:** This reagent forms an aryl halide. 2. **Reagent ii: KHS** - KHS introduces a thiol group (SH) in place of the diazonium group. - **Product:** Aryl thiol (not an aryl halide). - **Conclusion:** This reagent does not form an aryl halide. 3. **Reagent iii: CuCN / KCN** - This reagent replaces the diazonium group with a cyanide group (CN). - **Product:** Aryl cyanide (not an aryl halide). - **Conclusion:** This reagent does not form an aryl halide. 4. **Reagent iv: CuBr / HBr** - In this reaction, the diazonium group is replaced by a bromine atom (Br). - **Product:** Aryl bromide (Bromobenzene). - **Conclusion:** This reagent forms an aryl halide. 5. **Reagent v: Cu / HCl** - This reagent replaces the diazonium group with a chlorine atom (Cl). - **Product:** Aryl chloride (Chlorobenzene). - **Conclusion:** This reagent forms an aryl halide. 6. **Reagent vi: KI / Δ (Heat)** - In this case, the diazonium group is replaced by an iodine atom (I). - **Product:** Aryl iodide (Iodobenzene). - **Conclusion:** This reagent forms an aryl halide. 7. **Reagent vii: CH₃CH₂OH (Ethanol)** - This reagent does not replace the diazonium group with a halide; instead, it leads to the formation of a hydrocarbon. - **Product:** Benzene (not an aryl halide). - **Conclusion:** This reagent does not form an aryl halide. 8. **Reagent viii: H₃PO₂ / H₂O** - This reagent also does not replace the diazonium group with a halide; it leads to the formation of benzene. - **Product:** Benzene (not an aryl halide). - **Conclusion:** This reagent does not form an aryl halide. ### Summary of Findings: - Reagents that form aryl halides: - HBF₄ (i) - CuBr / HBr (iv) - Cu / HCl (v) - KI (vi) **Total Count of Reagents that Form Aryl Halides:** 4 ### Final Answer: **4 reagents react with arene diazonium salts to form aryl halides.** ---
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