Home
Class 12
PHYSICS
A particle moves with a velocity of (4ha...

A particle moves with a velocity of `(4hati-2hatj+2hatk)ms^(-1)` under the influence of a constant force `vecF=(10hati+3hatj-2hatk)N`. The instantaneous power applied to the particle is

Text Solution

Verified by Experts

The correct Answer is:
30
Promotional Banner

Similar Questions

Explore conceptually related problems

A particle moves with the velocity vecv=(5hati+2hatj-hatk)ms^(-1) under the influence of a constant force, vecF=(2hati+5hatj-10hatk)N. The instantaneous power applied is

A particle moves with the velocity vecv=(5hati+2hatj-hatk)ms^(-1) under the influence of a constant force, vecF=(2hati+5hatj-10hatk)N. The instantaneous power applied is

A particle moves with a velocity v=(5hati-3hatj + 6hatk) ms^(-1) under the influence of a constant force F =(10hati + 10hatj + 20hath) N , the instantaneous power applied to the particle is.

A particle moves with a velocity v=(5hati-3hatj + 6hatk) ms^(-1) under the influence of a constant force F =(10hati + 10hatj + 20hath) N , the instantaneous power applied to the particle is.

A body moves from a position vec(r_(1))=(2hati-3hatj-4hatk) m to a position vec(r_(2))=(3hati-4hatj+5hatk)m under the influence of a constant force vecF=(4hati+hatj+6hatk)N . The work done by the force is :

A particle of mass 2kg is moving in free space with velocity vecv_0=(2hati-3hatj+hatk)m//s is acted upon by force vecF=(2hati+hatj-2hatk)N . Find velocity vector of the particle 3s after the force starts acting.

A particle moves from point (hati+hatj) m to a point (6hati-2hatj) m under the action of force (10hati-2hatj) N. The work done by the force is

A particle moves from point P(1,2,3) to (2,1,4) under the action of a constant force F=(2hati+hatj+hatk)N . Work done by the force is

A particle moves from point P(1,2,3) to (2,1,4) under the action of a constant force F=(2hati+hatj+hatk)N . Work done by the force is

A particle is moving with a constant acceleration veca = hati-2hatj+2hatk m//s^(2) and instantaneous velocity vecv = hati+2hatj+2hatk m//s , then rate of change of speed of particle 2 second after this instant will be :