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Four successive members of the first row...

Four successive members of the first row transition elements are listed below with their atomic number. Which one of them is expected to have the highest third ionisation enthalpy ?

A

`Fe(Z=26)`

B

`Mn(Z=25)`

C

`Cr(Z=24)`

D

`Co(Z=27)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the four successive first-row transition elements has the highest third ionization enthalpy, we will analyze the electronic configurations and the stability of the resulting ions after the removal of electrons. ### Step-by-Step Solution: 1. **Identify the Elements and Their Electronic Configurations:** - Iron (Fe), Atomic Number 26: Electronic configuration is [Ar] 3d^6 4s^2. - Manganese (Mn), Atomic Number 25: Electronic configuration is [Ar] 3d^5 4s^2. - Chromium (Cr), Atomic Number 24: Electronic configuration is [Ar] 3d^5 4s^1. - Cobalt (Co), Atomic Number 27: Electronic configuration is [Ar] 3d^7 4s^2. 2. **Remove Two Electrons for the Third Ionization:** - For Iron (Fe): After removing two electrons, the configuration becomes [Ar] 3d^6 (removing 4s electrons). - For Manganese (Mn): After removing two electrons, the configuration becomes [Ar] 3d^5 (removing 4s electrons). - For Chromium (Cr): After removing two electrons, the configuration becomes [Ar] 3d^4 (removing 4s and one 3d electron). - For Cobalt (Co): After removing two electrons, the configuration becomes [Ar] 3d^7 (removing 4s electrons). 3. **Analyze the Stability of the Resulting Ions:** - Iron (Fe) will lose a third electron from the 3d^6 configuration. The resulting ion, Fe^3+, will have the configuration [Ar] 3d^5, which is half-filled and stable. - Manganese (Mn) has a half-filled 3d^5 configuration. Removing an electron from this stable configuration (Mn^2+) will require a significant amount of energy. - Chromium (Cr) will lose a third electron from the 3d^4 configuration, resulting in Cr^3+ with a configuration of [Ar] 3d^3, which is less stable than half-filled. - Cobalt (Co) will lose a third electron from the 3d^7 configuration, resulting in Co^3+ with a configuration of [Ar] 3d^6, which is also relatively stable. 4. **Determine the Highest Third Ionization Enthalpy:** - The third ionization enthalpy is highest for the element whose resulting ion configuration is the most stable. Since Mn^2+ has a half-filled 3d^5 configuration, it is very stable, making it difficult to remove another electron. - Therefore, the highest third ionization enthalpy will be for Manganese (Mn) because it requires a large amount of energy to remove an electron from a stable half-filled configuration. ### Conclusion: The element expected to have the highest third ionization enthalpy is **Manganese (Mn)**.
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