Identify X and Y in the following reaction `BCl_(3)+NH_(4)Cl overset(140^(@)C//C_(6)H_(5)Cl)rarr X overset(NaBH_(4))rarr Y`

Options

A. `X=NaBO_(2), Y=B_(2)O_(3)`
B. `X=Na_(2)B_(4)O_(7), Y=H_(3)BO_(3)`
C. `X=BN, Y=[NH_(4)]^(+)[BCl_(4)]^(-)`
D. `X=B_(3)N_(3)H_(3)Cl_(3), Y=B_(3)N_(3)H_(6)`

Answer

To solve the given problem, we need to identify the compounds X and Y in the reaction sequence provided. Let's break down the reaction step by step.

### Step 1: Identify the Reaction of BCl3 with NH4Cl
The first part of the reaction involves the interaction of boron trichloride (BCl3) with ammonium chloride (NH4Cl) at a high temperature (140°C) in the presence of chlorobenzene (C6H5Cl).

**Reaction:**
\[ \text{BCl}_3 + \text{NH}_4\text{Cl} \rightarrow \text{B}_3\text{N}_3\text{H}_3 + \text{Cl}_3 \]

In this reaction, BCl3 and NH4Cl combine to form a compound known as boron nitride, specifically trimeric boron nitride (B3N3H3), along with some chlorine.

### Step 2: Identify Compound X
From the reaction above, we can identify that:
- **X = B3N3H3 + Cl3**

### Step 3: Reaction of X with NaBH4
The next step involves the reaction of the product X with sodium borohydride (NaBH4).

**Reaction:**
\[ \text{B}_3\text{N}_3\text{H}_3 + \text{NaBH}_4 \rightarrow \text{B}_3\text{N}_3\text{H}_6 \]

In this reaction, the boron nitride compound (B3N3H3) reacts with sodium borohydride to form borazine (B3N3H6).

### Step 4: Identify Compound Y
From the reaction above, we can identify that:
- **Y = B3N3H6 (Borazine)**

### Final Answer
- **X = B3N3H3 + Cl3**
- **Y = B3N3H6 (Borazine)**

### Summary
Thus, the final answer is:
- **X = B3N3H3 + Cl3**
- **Y = B3N3H6 (Borazine)**