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The greatest term in the expansion of (3...

The greatest term in the expansion of `(3+2x)^(51)`, where `x=(1)/(5)`, is

A

`5^(th)` term

B

`6^(th)` term

C

`7^(th)` term

D

`9^(th)` term

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The correct Answer is:
To find the greatest term in the expansion of \((3 + 2x)^{51}\) where \(x = \frac{1}{5}\), we can follow these steps: ### Step 1: Identify the values of \(x\) and \(y\) In the expression \((3 + 2x)^{51}\), we can identify: - \(x = 3\) - \(y = 2x = 2 \cdot \frac{1}{5} = \frac{2}{5}\) ### Step 2: Use the formula for the greatest term The greatest term in the binomial expansion of \((x + y)^n\) occurs at the term \(T_r\), where: \[ r = \left\lfloor \frac{n + 1}{2} \cdot \frac{y}{x + y} \right\rfloor \] In our case, \(n = 51\), \(x = 3\), and \(y = \frac{2}{5}\). ### Step 3: Calculate \(r\) First, we need to calculate: \[ \frac{y}{x + y} = \frac{\frac{2}{5}}{3 + \frac{2}{5}} = \frac{\frac{2}{5}}{\frac{15}{5} + \frac{2}{5}} = \frac{\frac{2}{5}}{\frac{17}{5}} = \frac{2}{17} \] Now substituting this back into the formula for \(r\): \[ r = \left\lfloor \frac{51 + 1}{2} \cdot \frac{2}{17} \right\rfloor = \left\lfloor \frac{52}{2} \cdot \frac{2}{17} \right\rfloor = \left\lfloor 26 \cdot \frac{2}{17} \right\rfloor = \left\lfloor \frac{52}{17} \right\rfloor \] Calculating \(\frac{52}{17}\): \[ \frac{52}{17} \approx 3.0588 \] Thus, \(r = 3\). ### Step 4: Identify the term \(T_r\) The \(r\)-th term in the expansion is given by: \[ T_r = \binom{n}{r} x^{n-r} y^r \] Substituting \(n = 51\), \(r = 3\), \(x = 3\), and \(y = \frac{2}{5}\): \[ T_3 = \binom{51}{3} (3)^{51-3} \left(\frac{2}{5}\right)^3 \] ### Step 5: Calculate the binomial coefficient and powers Calculating \(\binom{51}{3}\): \[ \binom{51}{3} = \frac{51 \cdot 50 \cdot 49}{3 \cdot 2 \cdot 1} = 23425 \] Calculating \( (3)^{48} \) and \( \left(\frac{2}{5}\right)^3 \): \[ \left(\frac{2}{5}\right)^3 = \frac{8}{125} \] Thus, \[ T_3 = 23425 \cdot (3^{48}) \cdot \frac{8}{125} \] ### Step 6: Final calculation To find the greatest term, we can compute: \[ T_3 = \frac{23425 \cdot 8 \cdot 3^{48}}{125} \] ### Conclusion The greatest term in the expansion of \((3 + 2x)^{51}\) where \(x = \frac{1}{5}\) is: \[ T_3 = \frac{23425 \cdot 8 \cdot 3^{48}}{125} \]
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