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A uniform rod of length 2.0 m specific g...

A uniform rod of length 2.0 m specific gravity 0.5 and mass 2 kg is hinged at one end to the bottom of a tank of water (specific gravity = 10) filled upto a height o f 1.0 m as shown in figure. Taking the case `theta =- 0^(@)` the force exerted by the hings on the rod is `(g = 10 m//s^(2))`

A

10.2 N, upwards

B

4.2 N, downwards

C

8.3 N downwards

D

6.2 N, upwards

Text Solution

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The correct Answer is:
C
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