`{:(COOH),(|),(COOH):}overset(NaOH)rarr X`,
The product (X) will be

Options

A. `{:(CH_(2)ON a),(|),(COONa):}`
B. `{:(COOH),(|),(COOH):}`
C. `{:(COONa),(|),(COONa):}`
D. `{:(CH_(2)OH),(|),(CH_(2)OH):}`

Answer

To solve the problem, we need to analyze the reaction between oxalic acid and sodium hydroxide (NaOH). Here’s a step-by-step breakdown of the solution:

### Step 1: Identify the Reactants
The reactant given is oxalic acid, which has the formula HOOC-COOH. It consists of two carboxylic acid groups (COOH).

### Step 2: Write the Reaction
When oxalic acid reacts with sodium hydroxide (NaOH), an acid-base neutralization reaction occurs. The general reaction can be represented as:
\[ \text{HOOC-COOH} + 2 \text{NaOH} \rightarrow \text{COONa-COONa} + 2 \text{H}_2\text{O} \]

### Step 3: Determine the Products
In this reaction, oxalic acid (an acid) reacts with sodium hydroxide (a base) to form a salt and water. The salt formed is sodium oxalate (COONa), and water is also produced.

### Step 4: Write the Structure of the Product
The product can be represented as:
\[ \text{COONa} - \text{COONa} \]
This indicates that there are two sodium oxalate units formed.

### Step 5: Conclusion
The final product (X) of the reaction is sodium oxalate, which can be represented as:
\[ \text{X} = \text{COONa} - \text{COONa} \]

### Final Answer
The product (X) will be sodium oxalate (COONa) in the form of a dimer.

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