Identify (X), (Y) and (Z) in the given reaction.
`CH_(3)COCH_(3) overset(I_(2)+NaOH)underset("heat") to X overset(Ag)underset("heat") to Y overset(H_(2)SO_(4)//HgSO_(4))underset("heat") to Z`

Options

A. `X=CHI_(3), Y=CH_(3)CHO, Z=HCHO`
B. `X=CHI_(3), Y=CH_(3)OH, Z=CH_(3)CHO`
C. `X=CHI_(3), Y=CH-=CH, Z=CH_(3)CHO`
D. `X=CH_(3)COCl_(3), Y=CH_(2)=CH_(2), Z=CH_(3)CHO`

Answer

To solve the given reaction step by step, we will identify the compounds (X), (Y), and (Z) in the reaction sequence provided.

### Step 1: Identify (X)
The starting compound is **CH₃COCH₃** (acetone). When acetone is treated with **I₂** and **NaOH** under heat, it undergoes a reaction known as the iodoform reaction. This reaction leads to the formation of **CHI₃** (iodoform).

**Reaction:**
\[ \text{CH}_3COCH_3 \xrightarrow{I_2 + NaOH, \text{heat}} \text{CHI}_3 \]

Thus, **(X) = CHI₃**.

### Step 2: Identify (Y)
Next, the iodoform (CHI₃) is subjected to heat in the presence of **Ag**. In this reaction, the iodoform undergoes dehydrohalogenation, leading to the formation of an alkyne. The product formed is **C₂H₂** (ethyne), which can be represented as **CH≡CH**.

**Reaction:**
\[ \text{CHI}_3 \xrightarrow{Ag, \text{heat}} \text{CH} \equiv \text{CH} \]

Thus, **(Y) = CH≡CH**.

### Step 3: Identify (Z)
Finally, the alkyne (CH≡CH) undergoes oxymercuration followed by demercuration when treated with **H₂SO₄** and **HgSO₄** under heat. This reaction converts the alkyne into an aldehyde. The product formed is **CH₃CHO** (acetaldehyde).

**Reaction:**
\[ \text{CH} \equiv \text{CH} \xrightarrow{H_2SO_4/HgSO_4, \text{heat}} \text{CH}_3CHO \]

Thus, **(Z) = CH₃CHO**.

### Summary of Identifications
- **(X) = CHI₃**
- **(Y) = CH≡CH**
- **(Z) = CH₃CHO**

### Final Answer
The final answer is:
- **(X) = CHI₃**
- **(Y) = CH≡CH**
- **(Z) = CH₃CHO**