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Consider the line L-=(x-1)/(2)=(y+2)/(3)...

Consider the line `L-=(x-1)/(2)=(y+2)/(3)=(z-7)/(6)`. Point `P(2, -5, 0)` and Q are such that PQ is perpendicular to the line L and the midpoint of PQ lies on line L, then coordinates of Q are

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To solve the problem, we need to find the coordinates of point Q given the conditions that PQ is perpendicular to the line L and the midpoint of PQ lies on line L. ### Step 1: Understand the line L The line L is given in the symmetric form: \[ \frac{x-1}{2} = \frac{y+2}{3} = \frac{z-7}{6} \] From this, we can extract the direction ratios of the line: - Direction ratios: \( (2, 3, 6) \) ### Step 2: Define the coordinates of point Q Let the coordinates of point Q be \( (α, β, γ) \). The coordinates of point P are given as \( P(2, -5, 0) \). ### Step 3: Find the direction ratios of line PQ The direction ratios of line PQ can be expressed as: \[ (α - 2, β + 5, γ - 0) = (α - 2, β + 5, γ) \] ### Step 4: Use the condition of perpendicularity For PQ to be perpendicular to line L, the dot product of their direction ratios must equal zero: \[ 2(α - 2) + 3(β + 5) + 6(γ) = 0 \] Expanding this gives: \[ 2α - 4 + 3β + 15 + 6γ = 0 \] Simplifying, we have: \[ 2α + 3β + 6γ + 11 = 0 \quad \text{(Equation 1)} \] ### Step 5: Find the midpoint of PQ The midpoint M of segment PQ can be calculated as: \[ M = \left( \frac{2 + α}{2}, \frac{-5 + β}{2}, \frac{0 + γ}{2} \right) \] Since the midpoint M lies on line L, we can express the coordinates of M in terms of a parameter \( λ \): \[ M = (2λ + 1, 3λ - 2, 6λ + 7) \] ### Step 6: Set up equations for the midpoint Equating the coordinates of M with the coordinates from line L gives us: 1. \( \frac{2 + α}{2} = 2λ + 1 \) 2. \( \frac{-5 + β}{2} = 3λ - 2 \) 3. \( \frac{γ}{2} = 6λ + 7 \) From these equations, we can solve for \( α, β, γ \) in terms of \( λ \): 1. \( 2 + α = 4λ + 2 \) → \( α = 4λ \) 2. \( -5 + β = 6λ - 4 \) → \( β = 6λ + 1 \) 3. \( γ = 12λ + 14 \) ### Step 7: Substitute into Equation 1 Now substitute \( α, β, γ \) into Equation 1: \[ 2(4λ) + 3(6λ + 1) + 6(12λ + 14) + 11 = 0 \] Expanding this gives: \[ 8λ + 18λ + 3 + 72λ + 84 + 11 = 0 \] Combining like terms: \[ 98λ + 98 = 0 \] Thus, \[ λ = -1 \] ### Step 8: Find coordinates of Q Substituting \( λ = -1 \) back into the equations for \( α, β, γ \): 1. \( α = 4(-1) = -4 \) 2. \( β = 6(-1) + 1 = -5 \) 3. \( γ = 12(-1) + 14 = 2 \) ### Final Answer The coordinates of point Q are: \[ Q(-4, -5, 2) \]
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