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A point P moves such that the chord of c...

A point P moves such that the chord of contact of P with respect to the circle `x^(2)+y^(2)=4` passes through the point (1, 1). The coordinates of P when it is nearest to the origin are

A

(1, 2)

B

(2, 2)

C

(3, 3)

D

`(sqrt2, sqrt2)`

Text Solution

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The correct Answer is:
To solve the problem, we need to find the coordinates of point \( P(h, k) \) which moves such that the chord of contact with respect to the circle \( x^2 + y^2 = 4 \) passes through the point \( (1, 1) \). We also want to find the coordinates of \( P \) when it is nearest to the origin. ### Step-by-step Solution: 1. **Equation of the Circle**: The given circle is \( x^2 + y^2 = 4 \). This can be rewritten as \( x^2 + y^2 = r^2 \) where \( r = 2 \). 2. **Chord of Contact**: The chord of contact from an external point \( P(h, k) \) to the circle is given by the equation: \[ hx + ky = r^2 \] For our circle, this becomes: \[ hx + ky = 4 \] 3. **Condition for the Chord of Contact**: Since the chord of contact passes through the point \( (1, 1) \), we substitute \( x = 1 \) and \( y = 1 \) into the chord of contact equation: \[ h(1) + k(1) = 4 \] This simplifies to: \[ h + k = 4 \] 4. **Expressing \( h \) in terms of \( k \)**: From the equation \( h + k = 4 \), we can express \( h \) as: \[ h = 4 - k \] 5. **Distance from the Origin**: The distance \( d \) from the origin \( (0, 0) \) to the point \( P(h, k) \) is given by: \[ d = \sqrt{h^2 + k^2} \] Substituting \( h = 4 - k \): \[ d = \sqrt{(4 - k)^2 + k^2} \] 6. **Expanding the Distance**: We expand the expression: \[ d = \sqrt{(16 - 8k + k^2) + k^2} = \sqrt{16 - 8k + 2k^2} \] 7. **Minimizing the Distance**: To find the minimum distance, we can minimize the expression under the square root: \[ f(k) = 2k^2 - 8k + 16 \] This is a quadratic function in \( k \). 8. **Finding the Vertex**: The vertex of a quadratic \( ax^2 + bx + c \) occurs at \( k = -\frac{b}{2a} \): \[ k = -\frac{-8}{2 \cdot 2} = \frac{8}{4} = 2 \] 9. **Finding \( h \)**: Substitute \( k = 2 \) back into the equation for \( h \): \[ h = 4 - k = 4 - 2 = 2 \] 10. **Coordinates of Point \( P \)**: Thus, the coordinates of point \( P \) when it is nearest to the origin are: \[ (h, k) = (2, 2) \] ### Final Answer: The coordinates of \( P \) when it is nearest to the origin are \( (2, 2) \).
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