Home
Class 12
CHEMISTRY
The correct order of o^(-) bond lengths ...

The correct order of `o^(-)` bond lengths in `ClO^(-), ClO_(2)^(-), ClO_(3)^(-) and ClO_(4)^(-)` is

A

`ClO^(-) lt ClO_(2)^(-) lt ClO_(3)^(-) lt ClO_(4)^(-)`

B

`ClO_(4)^(-) lt ClO_(3)^(-) lt ClO_(2)^(-) lt ClO^(-)`

C

`ClO_(3)^(-) lt ClO_(4)^(-) gt Cl)O_(2)^(-) gt ClO^(-)`

D

`ClO_(4)^(-)=ClO_(3)^(-) = ClO_(2)^(-) = ClO^(-)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the correct order of O⁻ bond lengths in ClO⁻, ClO₂⁻, ClO₃⁻, and ClO₄⁻, we need to analyze the structures and bond types in each of these species. Here’s a step-by-step breakdown of the solution: ### Step 1: Draw the Lewis Structures 1. **ClO⁻ (Chlorite Ion)**: - Chlorine (Cl) is bonded to one oxygen (O) with a single bond. - The oxygen has three lone pairs. - Structure: Cl - O⁻ (single bond). 2. **ClO₂⁻ (Chlorate Ion)**: - Chlorine is bonded to one oxygen with a double bond and to another oxygen with a single bond. - The singly bonded oxygen has two lone pairs, while the doubly bonded oxygen has no lone pairs. - Structure: Cl = O (double bond) and Cl - O⁻ (single bond). 3. **ClO₃⁻ (Chlorate Ion)**: - Chlorine is bonded to two oxygens with double bonds and one oxygen with a single bond. - The singly bonded oxygen has one lone pair. - Structure: Cl = O (double bond), Cl = O (double bond), and Cl - O⁻ (single bond). 4. **ClO₄⁻ (Perchlorate Ion)**: - Chlorine is bonded to four oxygens with double bonds. - There are no lone pairs on any of the oxygens. - Structure: Cl = O (double bond) for all four oxygens. ### Step 2: Analyze Bond Types - The bond length is influenced by the type of bond: - **Single bonds** are longer than **double bonds**. - As the number of double bonds increases, the bond length decreases. ### Step 3: Determine the Order of Bond Lengths - **ClO⁻** has a single bond, which is the longest bond length. - **ClO₂⁻** has one single bond and one double bond, making it shorter than ClO⁻. - **ClO₃⁻** has two double bonds and one single bond, making it shorter than ClO₂⁻. - **ClO₄⁻** has all double bonds, making it the shortest bond length. ### Conclusion The order of O⁻ bond lengths from longest to shortest is: **ClO⁻ > ClO₂⁻ > ClO₃⁻ > ClO₄⁻**. ### Final Answer The correct order of O⁻ bond lengths is ClO⁻ > ClO₂⁻ > ClO₃⁻ > ClO₄⁻, which corresponds to option A.
Promotional Banner

Similar Questions

Explore conceptually related problems

The order of Cl - O bond energy in ClO^(-), ClO_(2)^(-), ClO_(3)^(-), CIO_(4)^(-) is

Which of the following species, do not show disproportionation reaction and why ? ClO^(-) , ClO_(2)^(-) , ClO_(3)^(-) and ClO_(4)^(-) Also write reaction for each of the species that disproportionates.

What is geometry of ClO_2^(ɵ),ClO_3^(ɵ) and ClO_4^(ɵ) ions?

Increasing order of bond angle of (Cl_(2)O, ClO_(2), Cl_(2)O_(7), I_(3)^(ɵ)) is

Correct order of strength of a pi-bond(s) are :- (i) BO_(3)^(3-)gtCO_(3)^(2-)gtNO_(2) (ii) ClO_(4)^(-)gtSO_(4)^(2-)gtPO_(4)^(3-) (iii) BF_(3)gtBCl_(3)gtBBr_(3) (iv) AlCl_(3)gtBCl_(3)

Write the disproportionation reaction of ClO^(-) to Cl^(-) and ClO_(3)^(-)

The number of a bonds in ClO_(4)^(-) ion is

If E_(ClO_(3)^(-)//ClO_(4)^(-))=-0.36 V & E_(ClO_(3)^(-)//ClO_(2)^(-))^(@)=0.33V at 300 K. The equilibrium concentration of perchlorate ion (ClO_(4)^(-)) which was initially 1.0 M in ClO_(3)^(-) when the reaction starts to attain the equilibrium, 2ClO_(3)^(-)hArr ClO_(2)^(-)+ClO_(4)^(-) Given : Anti log(0.509)=3.329

In the reaction :Cl_(2)+OH^(-)rarrCl^(-)+ClO_(4)^(-)+H_(2)O :-

Using VSEPR theory, predict the probable structures of SO_(3)^(2-),IF_(6)^(-),ClO_(4)^(-),Icl_(4)^(-) and Ibr_(2)^(-)