How many of these acids have `S-S` bonds?
`H_(2)S_(2)O_(3), H_(2)S_(2)O_(6), H_(2)S_(2)O_(7), H_(2)S_(2)O_(8), H_(2)SO_(5), H_(2)S_(n+2)O_(6)`.
(polythionic acid).

Answer

To determine how many of the given acids contain S-S bonds, we will analyze each compound one by one.

### Step 1: Analyze H₂S₂O₃
- The structure of H₂S₂O₃ can be represented as:
- H-O-S-S=O
- The S-S bond is present in this structure.
- **Conclusion**: H₂S₂O₃ has 1 S-S bond.

### Step 2: Analyze H₂S₂O₆
- The structure of H₂S₂O₆ can be represented as:
- H-O-S=O
- The S-S bond is present in this structure.
- **Conclusion**: H₂S₂O₆ has 1 S-S bond.

### Step 3: Analyze H₂S₂O₇
- The structure of H₂S₂O₇ can be represented as:
- H-O-S=O
- In this case, there is no S-S bond present.
- **Conclusion**: H₂S₂O₇ does not have an S-S bond.

### Step 4: Analyze H₂S₂O₈
- The structure of H₂S₂O₈ can be represented as:
- H-O-S=O
- There is no S-S bond present in this structure.
- **Conclusion**: H₂S₂O₈ does not have an S-S bond.

### Step 5: Analyze H₂SO₅
- The structure of H₂SO₅ can be represented as:
- H-O-S=O
- There is no S-S bond present in this structure.
- **Conclusion**: H₂SO₅ does not have an S-S bond.

### Step 6: Analyze H₂Sₙ₊₂O₆ (Polythionic acid)
- The structure of H₂Sₙ₊₂O₆ can be represented as:
- H-O-S-S=O
- The S-S bond is present in this structure.
- **Conclusion**: H₂Sₙ₊₂O₆ has 1 S-S bond.

### Final Count
- From the analysis:
- H₂S₂O₃: 1 S-S bond
- H₂S₂O₆: 1 S-S bond
- H₂S₂O₇: 0 S-S bonds
- H₂S₂O₈: 0 S-S bonds
- H₂SO₅: 0 S-S bonds
- H₂Sₙ₊₂O₆: 1 S-S bond

**Total Acids with S-S Bonds**: 3 acids (H₂S₂O₃, H₂S₂O₆, H₂Sₙ₊₂O₆).

### Summary
The total number of acids that contain S-S bonds is **3**.

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