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Let P(1):x+y+2z=3 and P(2):x-2y+z=4 be t...

Let `P_(1):x+y+2z=3 and P_(2):x-2y+z=4` be two planes. Let `A(2, 4 5) and B(4, 3, 8)` be two points in space. The equation of plane `P_(3)` through the line of intersection of `P_(1) and P_(2)` such that the length of the projection upon it of the line segment AB is the least, is

A

`2x-y+3z=7`

B

`3y+z+1=0`

C

`x+3y+z+2=0`

D

`3x-3y+4z-11=0`

Text Solution

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The correct Answer is:
A
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