Formaldehyde gives an additive product with Methylmagnesium iodide which in aqueous hydrolysis gives

Options

A. Isopropyl alcohol
B. Ethyl alcohol
C. Methyl alcohol
D. Propyl alcohol

Answer

To solve the problem, we need to understand the reaction between formaldehyde and methylmagnesium iodide (CH3MgI), followed by hydrolysis. Let's break it down step by step.

### Step 1: Identify the Reactants
The reactants in this reaction are:
- Formaldehyde (HCHO)
- Methylmagnesium iodide (CH3MgI)

### Step 2: Understand the Reaction
Methylmagnesium iodide is a Grignard reagent, which acts as a nucleophile. It will react with the carbonyl carbon of formaldehyde.

### Step 3: Form the Additive Product
When formaldehyde reacts with methylmagnesium iodide, the nucleophile (CH3-) attacks the electrophilic carbon of the carbonyl group (C=O) in formaldehyde. This results in the formation of an alkoxide intermediate:
\[ \text{HCHO} + \text{CH}_3\text{MgI} \rightarrow \text{CH}_3\text{CH}_2\text{OMgI} \]

### Step 4: Hydrolysis of the Alkoxide
The alkoxide (CH3CH2OMgI) is then subjected to hydrolysis in the presence of an acid (H3O+). During hydrolysis, the alkoxide is converted into an alcohol, and the magnesium salt is formed:
\[ \text{CH}_3\text{CH}_2\text{OMgI} + \text{H}_3\text{O}^+ \rightarrow \text{CH}_3\text{CH}_2\text{OH} + \text{Mg(OH)I} \]

### Step 5: Identify the Product
The product formed from the hydrolysis is:
- Ethyl alcohol (CH3CH2OH)

### Conclusion
Thus, the final product obtained from the reaction of formaldehyde with methylmagnesium iodide followed by hydrolysis is ethyl alcohol.

### Final Answer
The answer is **ethyl alcohol (CH3CH2OH)**.

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