In presence of concentrated alkalie `(OH^(-))`, trimethyl acetaldehyde undergoes the

Options

A. Aldol condensation
B. Witting reaction
C. Cannizzaro reaction
D. Perkin reaction

Answer

To solve the question regarding the reaction of trimethyl acetaldehyde in the presence of concentrated alkali (OH⁻), we can follow these steps:

### Step 1: Identify the Structure of Trimethyl Acetaldehyde
Trimethyl acetaldehyde, also known as 2,2-dimethylpropanal, has the following structure:

```
CH3
|
CH3 - C - CHO
|
CH3
```

### Step 2: Determine the Presence of Alpha Hydrogen
Alpha hydrogens are the hydrogens attached to the carbon adjacent to the carbonyl group (C=O). In the structure of trimethyl acetaldehyde, the carbonyl carbon is connected to three methyl groups (CH₃), and there are no hydrogens attached to the carbon adjacent to the carbonyl group.

### Step 3: Analyze the Reaction Conditions
The question states that the reaction occurs in the presence of concentrated alkali (OH⁻). We need to determine whether the reaction will undergo aldol condensation or Cannizzaro reaction.

### Step 4: Distinguish Between Aldol Condensation and Cannizzaro Reaction
- **Aldol Condensation**: This reaction occurs when there is at least one alpha hydrogen present. The aldehyde or ketone can undergo self-condensation to form β-hydroxy aldehydes or ketones.
- **Cannizzaro Reaction**: This reaction occurs in aldehydes that do not have alpha hydrogens. In this case, the aldehyde undergoes disproportionation in the presence of a strong base, resulting in the formation of an alcohol and a carboxylic acid.

### Step 5: Conclusion
Since trimethyl acetaldehyde has no alpha hydrogen, it cannot undergo aldol condensation. Therefore, it will undergo the Cannizzaro reaction.

### Final Answer
The reaction of trimethyl acetaldehyde in the presence of concentrated alkali (OH⁻) will undergo the Cannizzaro reaction.