Write the structures and IUPAC names of all the cyclic isomers (alcohols) with the molecular with the molecular formula `C_(4)H_(7)OH`.

Answer

To find all the cyclic isomers of alcohols with the molecular formula C₄H₇OH, we will systematically draw the structures and provide their IUPAC names.

### Step 1: Identify the basic structure
The molecular formula C₄H₇OH indicates that we have a total of 4 carbon atoms, 7 hydrogen atoms, and one hydroxyl (OH) group. Since we are looking for cyclic isomers, we will focus on forming rings with these atoms.

### Step 2: Draw the first cyclic isomer
1. **Cyclic Structure**: Start with a cyclopropane structure (3 carbon atoms in a ring) and add a methyl group and an OH group.
- Structure:
```
CH3
|
CH2-CH
|
CH2
|
OH
```
- **IUPAC Name**: 1-Methylcyclopropanol

### Step 3: Draw the second cyclic isomer
2. **Cyclic Structure**: Now, consider a cyclopropyl group with a hydroxyl group on a carbon that is not part of the ring (methyl group attached).
- Structure:
```
CH3
|
CH2-CH
|
CH2
|
OH
```
- **IUPAC Name**: Cyclopropylmethanol

### Step 4: Draw the third cyclic isomer
3. **Cyclic Structure**: Now, we can form a cyclobutane structure (4 carbon atoms in a ring) with the hydroxyl group on one of the carbons.
- Structure:
```
CH2
/ \
CH2 CH2
\ /
CH
|
OH
```
- **IUPAC Name**: Cyclobutanol

### Summary of Structures and Names
1. **1-Methylcyclopropanol**
2. **Cyclopropylmethanol**
3. **Cyclobutanol**