The chlorine end of the chlorine monoxide radical carries a charge of `+0.167e`. The bond length is 154.6 pm. Calculate the dipole moment of the radical in Debye units.
The chlorine end of the chlorine monoxide radical carries a charge of `+0.167e`. The bond length is 154.6 pm. Calculate the dipole moment of the radical in Debye units.
A
2.35 D
B
1.24 D
C
1.59 D
D
2.05 D
Text Solution
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The correct Answer is:
To calculate the dipole moment of the chlorine monoxide radical, we can follow these steps:
### Step 1: Identify the charge
The charge on the chlorine end of the chlorine monoxide radical is given as \( +0.167e \), where \( e \) is the elementary charge.
### Step 2: Convert the charge to ESU
The value of the elementary charge \( e \) is approximately \( 4.80 \times 10^{-10} \) ESU. Therefore, we can calculate the charge in ESU as follows:
\[
\text{Charge} = 0.167 \times 4.80 \times 10^{-10} \text{ ESU}
\]
### Step 3: Calculate the charge in ESU
Calculating the above expression:
\[
\text{Charge} = 0.167 \times 4.80 \times 10^{-10} = 8.016 \times 10^{-11} \text{ ESU}
\]
### Step 4: Convert bond length to centimeters
The bond length is given as \( 154.6 \) pm (picometers). We need to convert this to centimeters:
\[
\text{Bond length} = 154.6 \text{ pm} = 154.6 \times 10^{-12} \text{ m} = 154.6 \times 10^{-10} \text{ cm}
\]
### Step 5: Calculate the dipole moment
The dipole moment \( \mu \) can be calculated using the formula:
\[
\mu = \text{Charge} \times \text{Bond length}
\]
Substituting the values we have:
\[
\mu = (8.016 \times 10^{-11} \text{ ESU}) \times (154.6 \times 10^{-10} \text{ cm})
\]
### Step 6: Perform the multiplication
Calculating the dipole moment:
\[
\mu = 8.016 \times 10^{-11} \times 154.6 \times 10^{-10} = 1.240 \times 10^{-20} \text{ ESU cm}
\]
### Step 7: Convert dipole moment to Debye
To convert the dipole moment from ESU cm to Debye, we use the conversion factor \( 1 \text{ Debye} = 10^{-18} \text{ ESU cm} \):
\[
\mu = \frac{1.240 \times 10^{-20} \text{ ESU cm}}{10^{-18}} = 1.240 \times 10^{-2} \text{ Debye}
\]
### Step 8: Final result
Thus, the dipole moment in Debye is approximately:
\[
\mu \approx 1.24 \text{ Debye}
\]
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