The distance of the y - axis from from t...

The distance of the y - axis from from the center of the circle which lies in the first quadrant (see figure) and tangent to the lines `y=(1)/(2)x,y =4` and the x-axis is

A

`4+2sqrt5" units"`

B

`4-(8sqrt5)/(5)" units"`

C

`2+(6sqrt5)/(5)" units"`

D

`4-2sqrt5" units"`

Verified by Experts

The correct Answer is:

A

Similar Questions

Explore conceptually related problems

Area lying in the first quadrant and bounded by the circle x^2+y^2=4 and the lines x= 0 and x= 2 is:

Find the equation of the circle which lies in the first quadrant and touching each-co ordinate-axis at a distance of 2 units from the origin.

Area lying in the first quadrant and bounded by the circle x^(2)+y^(2)=4 the line x=sqrt(3)y and x-axis , is

Find the area of the region in the first quadrant enclosed by the x-axis, the line y" "=" x" , and the circle x^2+y^2=32 .

Find the area bounded by the curve y=sqrtx,x=2y+3 in the first quadrant and X-axis.

Find the area of the region in the first quadrant enclosed by x-axis, the line y=sqrt(3\ )x and the circle x^2+y^2=16

Find the equation of the circle which touches the lines x=0, y=0 and x=4 and lies in the first quadrant.

The area (in sq. units) of the region in the first quadrant bounded by y=x^(2), y=2x+3 and the y - axis is

Area of the region in the first quadrant exclosed by the X-axis, the line y=x and the circle x^(2)+y^(2)=32 is

Find the area of the region in the first quadrant enclosed by the y-axis, the line y=x and the circle x^2+y^2=32 , using integration.