If sin^6 theta + cos^6 theta + k sin^2 2...

If `sin^6 theta + cos^6 theta + k sin^2 2theta`=1 , then k is equal to :

A

`(1)/(2)tan^(2)2 theta`

B

`(1)/(4)tan^(2)2theta`

C

`4cot^(2)theta`

D

`(3)/(4)tan^(2)2theta`

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The correct Answer is:

D

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