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The equetion of a wave travelling on a s...

The equetion of a wave travelling on a string is
`y = 4 sin(pi)/(2)(8t-(x)/(8))`
if x and y are in centimetres, then velocity of waves is

A

`64cms^(-1)" in "-x" direction"`

B

`32cms^(-1)" in "-x" direction"`

C

`32cms^(-1)" in "+x" direction"`

D

`64cms^(-1)" in "+x" direction"`

Text Solution

AI Generated Solution

The correct Answer is:
To find the velocity of the wave described by the equation \( y = 4 \sin\left(\frac{\pi}{2}(8t - \frac{x}{8})\right) \), we will follow these steps: ### Step 1: Identify the wave equation The general form of a wave equation is: \[ y = A \sin(\omega t - kx) \] where: - \( A \) is the amplitude, - \( \omega \) is the angular frequency, - \( k \) is the wave number. ### Step 2: Rewrite the given equation The given equation can be rewritten as: \[ y = 4 \sin\left(\frac{\pi}{2}(8t - \frac{x}{8})\right) \] This can be expanded to: \[ y = 4 \sin\left(4\pi t - \frac{\pi}{16} x\right) \] Here, we can identify: - \( \omega = 4\pi \) - \( k = \frac{\pi}{16} \) ### Step 3: Calculate the velocity of the wave The velocity \( v \) of the wave can be calculated using the formula: \[ v = \frac{\omega}{k} \] Substituting the values of \( \omega \) and \( k \): \[ v = \frac{4\pi}{\frac{\pi}{16}} \] ### Step 4: Simplify the expression To simplify: \[ v = 4\pi \times \frac{16}{\pi} \] The \( \pi \) cancels out: \[ v = 4 \times 16 \] \[ v = 64 \text{ cm/s} \] ### Step 5: Determine the direction of wave propagation Since the wave equation is in the form \( \sin(\omega t - kx) \), it indicates that the wave is traveling in the positive x-direction. ### Final Answer The velocity of the wave is: \[ \text{Velocity} = 64 \text{ cm/s} \text{ in the positive x-direction} \] ---
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