In input in a full - wave rectifier is `e=50 sin(314t)" volt"`, diode resistance is `100Omega` and load resistance is `1kOmega` then, pulse frequency of output voltage is

Options

A. 50 Hz
B. 100 Hz
C. 150 Hz
D. 200 Hz

Answer

To find the pulse frequency of the output voltage in a full-wave rectifier given the input voltage, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Input Voltage Function**:
The input voltage is given as:
\[ e = 50 \sin(314t) \text{ volts} \]

2. **Determine the Angular Frequency (\(\omega\))**:
In the general form of a sine wave, \(E = E_0 \sin(\omega t)\), we can identify \(\omega\) from the equation:
\[ \omega = 314 \text{ rad/s} \]

3. **Calculate the Frequency (\(f\))**:
The relationship between angular frequency (\(\omega\)) and frequency (\(f\)) is given by:
\[ \omega = 2\pi f \]
Rearranging this gives:
\[ f = \frac{\omega}{2\pi} \]
Substituting the value of \(\omega\):
\[ f = \frac{314}{2 \times 3.14} = \frac{314}{6.28} \approx 50 \text{ Hz} \]

4. **Determine the Output Frequency for a Full-Wave Rectifier**:
In a full-wave rectifier, the output frequency is double the input frequency. Therefore:
\[ f' = 2f \]
Substituting the value of \(f\):
\[ f' = 2 \times 50 = 100 \text{ Hz} \]

5. **Final Answer**:
The pulse frequency of the output voltage is:
\[ \boxed{100 \text{ Hz}} \]