Home
Class 12
PHYSICS
A block of mass 2kg is kept at the origi...

A block of mass 2kg is kept at the origin at t = 0 and is having velocity `4sqrt5ms^(-1)` in the positive x - direction. The only force on it is a conservative and its potential energy is defined as
`U=-x^(3)+6x^(2)+15`. Its velocity when the force acting on it is minimum (after the time t = 0 ) is -

A

`8m//s`

B

`4m//s`

C

`10sqrt(24)m//s`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

A block of mass 2 kg is kept at origin at t = 0 and is having velocity 4sqrt5m//s in positive x - direction. The only force on it is a conservative and its potential energy is defined as U=-x^(3)+6x^(2)+15 (SI units). Its velocity when the force acting on it is minimum (after the time t = 0 ) is

A block of mass 2 kg is having velocity 4sqrt(5) ms^(-1) in the positive x - direction at the origin. The only force acting on it is F = (3x^2 - 12 x)N . Its velocity when it is at x = 2 m is

A body of mass 6 kg is acted on a by a force so that its velocity changes from 3 ms^(-1) to 5ms^(-1) , then change in momentum is

A particle of mass m is at rest at the origin at time t=0 It is subjected to a force F(t)=F_(0)e^(-bt) in the X-direction. Its speed V(t) is depicted by which of the following curves

A particle of mass m is at rest the origin at time t= 0 . It is subjected to a force F(t) = F_(0) e^(-bt) in the x - direction. Its speed v(t) is depicted by which of the following curves ?

A block of mass 2 kg is kept on a rough horizontal floor an pulled with a force F. If the coefficient of friction is 0.5. then the minimum force required to move the block is :-

A particle of mass 3 kg is moving along x - axis and its position at time t is given by equation x=(2t^(2)+5)m . Work done by all the force acting on it in time interval t=0 to t=3s is

A particle slides on frictionless x - y plane. It is acted on by a conservative force described by the potential - energy function U(x, y) =(1)/(2)k(x^(2)+y^(2)) . Derive an expression for the force acting on the particle.

If acceleration a(t) = 3t^(2) and initial velocity u=0 m/s , then the velocity of the particle after time t=4 s

A block of mass 2 kg is free to move along the x -axis. It at rest and from t = 0 onwards it is subjected to a time-dependent force F(t) in the x direction. The force F(t) varies with t as shown in the figure. The kinetic energy of the block after 4.5 seconds is