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In a typical Mendelian cross, which is a...

In a typical Mendelian cross, which is a dihybrid cross, one parent is homozygous for both dominant traits and another parent is homozygous for both recessive traits. In the `F_(2)` -generation, both parental combination and recombinantions appear. The phenotypic ratio of parental combinations to recombinations is

A

2.42

B

1.50

C

1.37

D

1.66

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To solve the problem regarding the phenotypic ratio of parental combinations to recombinations in a typical Mendelian dihybrid cross, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Cross**: - We have two traits, let's say Trait A and Trait B. - One parent is homozygous dominant for both traits (AA BB). - The other parent is homozygous recessive for both traits (aa bb). 2. **F1 Generation**: - When these two parents are crossed, all offspring (F1 generation) will be heterozygous for both traits (Aa Bb). - The F1 generation will display the dominant phenotype for both traits. 3. **Selfing the F1 Generation**: - When we self the F1 generation (Aa Bb x Aa Bb), we need to determine the phenotypic ratios in the F2 generation. 4. **Using the Punnett Square**: - A dihybrid cross can be represented using a 4x4 Punnett square. - The possible gametes from Aa Bb are AB, Ab, aB, and ab. - The resulting combinations in the F2 generation will yield the following phenotypic ratio: - 9 (A_B_) : 3 (A_bb) : 3 (aaB_) : 1 (aabb) 5. **Identifying Parental and Recombinant Types**: - Parental combinations (same as the parents) are: - A_B_ (dominant for both traits) - aabb (recessive for both traits) - Recombinant combinations (different from the parents) are: - A_bb (dominant for A, recessive for B) - aaB_ (recessive for A, dominant for B) 6. **Counting the Combinations**: - From the phenotypic ratio: - Parental combinations = 9 (A_B_) + 1 (aabb) = 10 - Recombinant combinations = 3 (A_bb) + 3 (aaB_) = 6 7. **Calculating the Ratio**: - The ratio of parental combinations to recombinant combinations is: - Parental:Recombinant = 10:6 - This simplifies to 5:3. ### Final Answer: The phenotypic ratio of parental combinations to recombinations in the F2 generation is **5:3**.
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