An `alpha` particle is bombarded on `^14N`. As a result, a `^17O` nucleus is formed and a particle is emitted. This particle is a

Options

A. neutron
B. proton
C. electorn
D. positron

Answer

To solve the problem, we need to analyze the nuclear reaction that occurs when an alpha particle is bombarded on a nitrogen-14 nucleus.

### Step-by-Step Solution:

1. **Identify the Reaction Components**:
- The alpha particle is represented as \( ^4_2He \).
- The nitrogen nucleus is represented as \( ^{14}_7N \).
- The resulting nucleus is \( ^{17}_8O \) (oxygen-17).
- We need to determine the emitted particle, which we will denote as \( X \).

2. **Write the Nuclear Reaction**:
The reaction can be represented as:
\[ ^{14}_7N + ^{4}_2He \rightarrow ^{17}_8O + X \]

3. **Apply Conservation of Charge**:
The total charge before and after the reaction must be equal. The charge of nitrogen is +7, the charge of the alpha particle is +2, and the charge of oxygen is +8. Let \( Z \) be the charge of the emitted particle \( X \):
\[ 7 + 2 = 8 + Z \]
Simplifying this gives:
\[ 9 = 8 + Z \implies Z = 1 \]

4. **Apply Conservation of Mass**:
The total mass number before and after the reaction must also be equal. The mass number of nitrogen is 14, the mass number of the alpha particle is 4, and the mass number of oxygen is 17. Let \( A \) be the mass number of the emitted particle \( X \):
\[ 14 + 4 = 17 + A \]
Simplifying this gives:
\[ 18 = 17 + A \implies A = 1 \]

5. **Identify the Emitted Particle**:
The emitted particle \( X \) has a charge of +1 and a mass number of 1. This corresponds to a proton, which can also be represented as \( ^1_1H \).

### Conclusion:
The emitted particle is a proton.

### Final Answer:
The emitted particle is a proton.

---