Calculate the number of equivalents in 10 litre of `0.5 Mba(OH)_(2)` solution (Ba = 137)

Options

A. 0.1
B. 10
C. 100
D. 1

Answer

To calculate the number of equivalents in a 10-liter solution of 0.5 M Ba(OH)₂, we will follow these steps:

### Step 1: Determine the valency of Ba(OH)₂
Ba(OH)₂ dissociates in solution to give Ba²⁺ and 2 OH⁻ ions. The valency (n_f) of Ba(OH)₂ is 2 because it can donate 2 hydroxide ions (OH⁻) per formula unit.

### Step 2: Calculate the normality (N) of the solution
Normality (N) is related to molarity (M) and the valency (n_f) as follows:
\[ N = n_f \times M \]
Given that the molarity (M) of the solution is 0.5 M and the valency (n_f) is 2:
\[ N = 2 \times 0.5 = 1 \, \text{N} \]

### Step 3: Calculate the number of equivalents
The number of equivalents can be calculated using the formula:
\[ \text{Number of equivalents} = N \times V \]
Where:
- N is the normality (1 N)
- V is the volume of the solution in liters (10 L)

Substituting the values:
\[ \text{Number of equivalents} = 1 \, \text{N} \times 10 \, \text{L} = 10 \, \text{equivalents} \]

### Conclusion
The number of equivalents in 10 liters of 0.5 M Ba(OH)₂ solution is **10 equivalents**.

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