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Arrange the following compounds in decre...

Arrange the following compounds in decreasing order of acidity.
(i) `ClCH_(2)CH_(2)CH_(2)COOH`
(ii) `CH_(3)CHClCH_(2)COOH`
(iii) `CH_(3)CH_(2)CHClCOOH`

A

`I gt II gt III`

B

`III gt II gt I`

C

`I gt III gt II`

D

`III gt I gt II`

Text Solution

AI Generated Solution

The correct Answer is:
To arrange the compounds in decreasing order of acidity, we need to analyze the structure of each compound and the effects of substituents on acidity. ### Step-by-Step Solution: 1. **Identify the Compounds**: - (i) `ClCH₂CH₂CH₂COOH` (Compound A) - (ii) `CH₃CHClCH₂COOH` (Compound B) - (iii) `CH₃CH₂CHClCOOH` (Compound C) 2. **Understand Acidity**: - Acidity is determined by the ability of a compound to donate protons (H⁺ ions). - The presence of electron-withdrawing groups (EWGs) increases acidity by stabilizing the negative charge on the conjugate base formed after deprotonation. - Conversely, electron-donating groups (EDGs) decrease acidity. 3. **Analyze Each Compound**: - **Compound A**: `ClCH₂CH₂CH₂COOH` - The Cl group is attached to the first carbon. It has a -I (inductive) effect, but it is relatively far from the carboxylic acid group, which reduces its effectiveness in stabilizing the conjugate base. - **Compound B**: `CH₃CHClCH₂COOH` - The Cl group is on the second carbon, closer to the carboxylic acid group. This means it has a stronger -I effect compared to Compound A, thus increasing the acidity more effectively. - **Compound C**: `CH₃CH₂CHClCOOH` - The Cl group is on the third carbon. While it still exerts a -I effect, it is further away from the carboxylic acid group than in Compound B, making it less effective in stabilizing the conjugate base compared to Compound B. 4. **Order of Acidity**: - Based on the analysis, the order of acidity can be determined as follows: - Compound B (CH₃CHClCH₂COOH) has the highest acidity due to the Cl group being closest to the carboxylic acid group. - Compound C (CH₃CH₂CHClCOOH) is next, as the Cl group is still an EWG but further away. - Compound A (ClCH₂CH₂CH₂COOH) has the lowest acidity due to the Cl group being the farthest from the carboxylic acid group. ### Final Order: The decreasing order of acidity is: **(ii) > (iii) > (i)** or **B > C > A**.
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