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The major product formed in the reactio...

The major product formed in the reaction
`CH_(3)CH = CH - overset(O)overset(||)(C ) - CH_(3)underset(H_(2)O,CH_(3)OH)overset(NaBH_(4))rarr` is

Text Solution

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The correct Answer is:
To solve the problem, we need to analyze the reaction step by step: 1. **Identify the Reactants**: The reactant is 3-penten-2-one (CH3CH=CHC(=O)CH3), which contains a double bond and a ketone functional group. 2. **Identify the Reagent**: The reagent used is sodium borohydride (NaBH4), which is a mild reducing agent. It is known to reduce ketones to secondary alcohols and aldehydes to primary alcohols, but it does not reduce alkenes (double bonds). 3. **Reaction Mechanism**: Since we have a ketone (the carbonyl group C=O) in the molecule, NaBH4 will react with this carbonyl group. The double bond (C=C) will remain unaffected because NaBH4 does not reduce alkenes. 4. **Reduction of the Ketone**: The ketone group (C=O) will be reduced to a secondary alcohol (C-OH). The structure of the product will now include the unchanged double bond and the newly formed hydroxyl group (OH) from the reduction of the ketone. 5. **Final Structure of the Product**: After the reduction, the structure of the major product will be CH3CH=CHC(OH)CH3. This is 3-pentanol, where the ketone has been converted to a secondary alcohol. 6. **Conclusion**: The major product formed in the reaction is 3-pentanol. ### Final Answer: The major product formed is **3-pentanol (CH3CH=CHC(OH)CH3)**.
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What is the major product formed in the following reaction CH_(3)O -overset(OH)overset(|)(CH) -underset(CH_(3))underset(|)(CH)-CH_(3) + HBr to

What is the major porduct formed in the following reaction ? CH_(3)O-overset(OH)overset(|)(CH)-underset(CH_(3))underset(|)(CH)-CH_(3)+ HBrrarr

Knowledge Check

  • The major product formed in the following reaction is CH_3-underset(H)underset(|)overset(CH_3)overset(|)C-CH_2Brunderset(CH_3OH)overset(CH_3O^(-))to

    A
    `CH_3-underset(H)underset(|)overset(CH_3)overset(|)C-CH_2OCH_3`
    B
    `CH_3-underset(OCH_3)underset(|)(CH)-CH_2CH_3`
    C
    `CH_3-overset(CH_3)overset(|)C=CH_2`
    D
    `CH_3-underset(OCH_3)underset(|)overset(CH_3)overset(|)C-CH_3`

  • CH_(3)CH_(2)-overset(O)overset(||)(C)-CH_(3)underset(HCl)overset(NaNO_(2))to , Major product of this reaction is :

    A
    `CH_(3)underset(NO)underset(|)(C)H-overset(O)overset(||)(C)-CH_(3)`
    B
    `CH_(3)-CH_(2)-overset(O)overset(||)(C)-CH=N-OH`
    C
    D

  • CH_(3)-CH=CH_(2)underset(H_(2)O_(2)//OH^(-))overset(BD_(3))rarr"product X" , X is :

    A
    `CH_(3)-underset(OH)underset(|)(CH)-CH_(2)D`
    B
    `CH_(3)-underset(D)underset(|)(CH)-CH_(2)OD`
    C
    `CH_(3)-underset(OD)underset(|)(CH)-CH_(3)`
    D
    none is correct

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    The major product formed in the following reation is CH_(3)-underset(H)underset(|)overset(CH_(3))overset(|)C-CH_(2)-Br underset(CH_(3)OH)overset(CH_(3)ONa)rarr .

    The major product (Y)in the following reaction sequency is : CH_(3) - overset( CH_(3))overset(|)(C)H - CH= CH_(2) overset( Br_(2) //H_(2)O)(rarr) X overset("conc."H_(2)SO_(4)//Delta)(rarr)Y

    The major product [B] in the following reaction is : CH_(3)-CH_(3)-overset(CH)overset("| ")"CH"-CH_(2)-OCH_(2)-CH_(3)overset(HI)underset("Heat")rarr [A]" alcohol"overset(H_(2)SO_(4))underset(Delta)rarr [B]

    End product of this conversion CH_(3)-overset(O)overset(||)(C)-CH_(2)-CH_(2)-CH_(2)-CO_(2)H overset(1. NaBH_(4))underset(2.H_(2)O,H^(+))to is

    The major product of the following reaction is : CH_(3)underset(overset(|)(Br))(C)HCH_(2)underset(overset(|)(Br))(C)HCH_(2)CH_(3) underset("heat")overset(KOH, CH_(3)OH)(to)

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