`2DCDO overset(OH^(-))rarr [X] and [Y]` are

Options

A. `DCOO^(-), D_(2)CHOH`
B. `HCOO^(-), CH_(3)OH`
C. `HCOO^(-), CD_(3)OH`
D. `DCOO^(-), CD_(3)OH`

Answer

To solve the question regarding the reaction of 2 moles of D-C-D-O in the presence of hydroxide (OH^(-)), we need to identify the products X and Y formed in this reaction, which is a type of Cain-Zarro reaction.

### Step-by-Step Solution:

1. **Identify the Reaction Type**:
- The reaction is identified as a Cain-Zarro reaction, which involves two moles of carbonyl compounds that do not have alpha-hydrogens.

2. **Understand the Reactants**:
- The reactant is D-C-D-O, which is a deuterated carbonyl compound (D indicates deuterium, a hydrogen isotope).

3. **Presence of Hydroxide Ion**:
- The presence of hydroxide (OH^(-)) indicates that the reaction will involve both oxidation and reduction processes.

4. **Oxidation Process**:
- In the oxidation step, the carbonyl compound will be converted into a carboxylate ion. The general formula for a carboxylate ion derived from a carbonyl compound is RCOO^(-). In this case, it will be D-C(=O)O^(-).

5. **Reduction Process**:
- In the reduction step, the carbonyl compound will be reduced to an alcohol. The product will typically be in the form of R-OH. Here, it will be D-C-OH (deuterated alcohol).

6. **Final Products**:
- Therefore, the products of the reaction are:
- Product X: Carboxylate ion (D-C(=O)O^(-))
- Product Y: Alcohol (D-C-OH)

### Conclusion:
The products X and Y formed from the reaction of 2 moles of D-C-D-O in the presence of hydroxide are:
- X: D-C(=O)O^(-) (Carboxylate ion)
- Y: D-C-OH (Deuterated alcohol)