Home
Class 12
PHYSICS
If a simple harmonic oscillator has got ...

If a simple harmonic oscillator has got a displacement of `0.02 m` and acceleration equal to `2.0 m//s^(2)` at any time, the angular frequency of the oscillator is equal to

A

`"100 rad s"^(-1)`

B

`"10 rad s"^(-1)`

C

`"1 rad s"^(-1)`

D

`"0.1 rad s"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

If a simple harmonic oscillator has got a displacement of 0.02m and acceleration equal to 2.0ms^-2 at any time, the angular frequency of the oscillator is equal to

A particle executing SHM has a maximum speed of 0.5ms^(-1) and maximum acceleration of 1.0ms^(-2) . The angular frequency of oscillation is

If x is the displacement of a simple harmonic oscillator at a certain instant and y its acceleration at that instant, draw graph of (x, y) at all instant in one complete oscillation,

A pendulum is hung the roof of a sufficiently high huilding and is moving freely to and fro like a simple harmonic oscillator .The acceleration of the bob of the pendulum is 20m//s^(2) at a distance of 5m from the meanposition .The time period of oscillation is

A simple harmonic motion is represented by x(t) = sin^2 omegat - 2 cos^(2) omegat . The angular frequency of oscillation is given by

A particle executes simple harmonic motion and is located at x = a, b and c at times t_(0), 2t_(0) and 3t_(0) respectively. The frequency of the oscillation is :

A weakly damped harmonic oscillator of frequency n_1 is driven by an external periodic force of frequency n_2 . When the steady state is reached, the frequency of the oscillator will be

Acceleration displacement (a-x) graph of a particle executing S.H.M. is shown in the figure. The frequency of oscillation is (tan theta =8)

The equation of a damped simple harmonic motion is m(d^2x)/(dt^2)+b(dx)/(dt)+kx=0 . Then the angular frequency of oscillation is