`CH_(3)-CH=CH-CHOH-CH_(3)overset("Jones")underset("reagent")rarr`
Product is ?

Options

A. `CH_(3)-CH_(2)-CH_(2)-underset(O)underset(||)C-CH_(3)`
B. `CH_(3)-CH=CH-underset(O)underset(||)C-CH_(3)`
C. `CH_(3)-CH_(2)-CH_(2)-underset(OH)underset("| ")"CH"-CH_(3)`
D. `CH_(3)-CH_(2)-COOH`

Answer

To solve the question regarding the reaction of the compound CH₃-CH=CH-CHOH-CH₃ with Jones reagent, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Compound**: The given compound is CH₃-CH=CH-CHOH-CH₃. This compound has a double bond between the second and third carbon atoms and a hydroxyl (OH) group on the fourth carbon.

2. **Understand the Jones Reagent**: The Jones reagent is a mixture of chromium trioxide (CrO₃) in sulfuric acid (H₂SO₄) and water. It is commonly used for the oxidation of alcohols.

3. **Determine the Reaction Type**: The presence of the hydroxyl (OH) group means that the compound can undergo oxidation. The Jones reagent will oxidize the alcohol to a ketone.

4. **Identify the Site of Oxidation**: In the given compound, the hydroxyl group (OH) is located on the fourth carbon. When oxidized, this OH group will convert into a carbonyl group (C=O), specifically forming a ketone.

5. **Draw the Product**: After the oxidation, the structure will change from CH₃-CH=CH-CHOH-CH₃ to CH₃-CH=CH-C(=O)-CH₃. This compound is a ketone.

6. **Name the Product**: The resulting compound has a total of five carbon atoms with a ketone functional group at the third carbon. Therefore, the IUPAC name of the product is pent-3-one.

7. **Select the Correct Option**: Based on the naming, the product is pent-3-one, which corresponds to option B in the question.

### Final Answer:
The product formed is **pent-3-one** (option B).