Metal chloride A is soluble in hot water but insoluble in cold water. Select correct statement about A. Thus

Options

A. A can give yellow ppt. with `K_(2)CrO_(4)`
B. A can give white ppt with `K_(2)SO_(4)`
C. A can give yellow ppt with Kl
D. All of the above are correct statements.

Answer

To solve the problem regarding metal chloride A, which is soluble in hot water but insoluble in cold water, we need to analyze the properties of metal chlorides and their reactions with other compounds.

### Step-by-Step Solution:

1. **Understanding Solubility**:
- Metal chloride A is soluble in hot water but not in cold water. This behavior is often observed in certain metal chlorides, particularly those of alkaline earth metals or transition metals.

2. **Reactions with K2CrO4**:
- When metal chloride A (let's assume it is of the form MCl2) reacts with potassium chromate (K2CrO4), it can form a yellow precipitate of metal chromate (MCrO4).
- The reaction can be represented as:
\[ MCl2 + K2CrO4 \rightarrow MCrO4 \downarrow + 2 KCl \]
- This indicates that metal chloride A can give a yellow precipitate with K2CrO4.

3. **Reactions with K2SO4**:
- Metal chloride A can also react with potassium sulfate (K2SO4) to form a white precipitate of metal sulfate (MSO4).
- The reaction can be represented as:
\[ MCl2 + K2SO4 \rightarrow MSO4 \downarrow + 2 KCl \]
- This indicates that metal chloride A can give a white precipitate with K2SO4.

4. **Reactions with KI**:
- Metal chloride A can react with potassium iodide (KI) to form a yellow precipitate of metal iodide (MI2).
- The reaction can be represented as:
\[ MCl2 + 2 KI \rightarrow MI2 \downarrow + 2 KCl \]
- This indicates that metal chloride A can give a yellow precipitate with KI.

5. **Conclusion**:
- Based on the reactions above, we can conclude that metal chloride A can give a yellow precipitate with K2CrO4, a white precipitate with K2SO4, and a yellow precipitate with KI.
- Therefore, the correct statement about metal chloride A is that it can give yellow precipitate with K2CrO4, white precipitate with K2SO4, and yellow precipitate with KI. Thus, the answer is "All of the above."