Home
Class 12
CHEMISTRY
Equilibrium constant K(p) for the reacti...

Equilibrium constant `K_(p)` for the reaction `CaCO_(3)(s) hArr CaO(s) + CO_2(g)` is 0.82 atm at `727^@C`.
If 1 mole of `CaCO_(3)` is placed in a closed container of 20 L and heated to this temperature, what amount of `CaCO_(3)` would dissociate at equilibrium?

A

0.2 g

B

80 g

C

20 g

D

50 g

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

For the reaction CaCO_(3(s)) hArr CaO_((s))+CO_(2(g))k_p is equal to

At 27^(@)C, K_(p) value for the reaction CaCO_(3)(s) hArr CaO (s) + CO_(2)(g) , is 0.1 atm. K_(C) value for this reaction is

At 27^(@)C, K_(p) value for the reaction CaCO_(3)(s) hArr CaO (s) + CO_(2)(g) , is 0.2 atm. K_(C) value for this reaction is

For CaCO_(3)(s) hArr CaO(s)+CO_(2)(g), K_(c) is equal to …………..

At 27^(@)C, K_(p) value for the reaction CaCO_(3)(s) hArr CaO (s) + CO_(2)(g) , is 2 atm. K_(C) value for this reaction is

For the reaction CaCO_3(s) hArr CaO(s) +CO_2(g) , the pressure of CO_2 depends on

The reaction CaCO_(3)(s) hArr CaO(s)+CO_(2)(g) reaches the state of equilibrium when

Write expression for K_(p)"and"K_(c) for the reaction CaCO_(3)(S)harrCaO(S)+CO_(2)(g) .

For the reaction XCO_(3)hArrXO(s)+CO_(2)(g),Kp=1.64 atm "at 727^(@)C ". If 4 moles of" XCO_(3)(s) was put into a 50 litre container and heated to 727^(@)C What mole percent of the XCO_(3) remains unreacted at equilibrium ?

Equilibrium constant for the reaction, CaCO_(3)(s)hArr CaO(s)+CO_(2)(g) at 127^(@)C in one litre container is 8.21xx10^(-3) atm. Moles of CO_(2) at equilibrium is