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A "bar" magnet is at right angles to a u...

A "bar" magnet is at right angles to a uniform magnetic field. The couple acting on the magnet is to be one fourth by rotating it from the position. The angle of rotation is

A

`60^(@)`

B

`45^(@)`

C

`30^(@)`

D

`75^(@)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will use the concepts of torque acting on a magnetic dipole in a magnetic field. ### Step-by-Step Solution: 1. **Understanding the Initial Condition**: - A bar magnet is initially positioned at a right angle (90 degrees) to a uniform magnetic field. This means that the angle θ = 90°. 2. **Calculating the Initial Torque**: - The torque (τ) acting on a magnetic dipole in a magnetic field is given by the formula: \[ \tau = m \cdot B \cdot \sin(\theta) \] - Here, \(m\) is the magnetic moment of the bar magnet, \(B\) is the magnetic field strength, and \(\theta\) is the angle between the magnetic moment and the magnetic field. - Since θ = 90°, we have: \[ \tau_1 = m \cdot B \cdot \sin(90°) = m \cdot B \cdot 1 = mB \] 3. **Condition After Rotation**: - The problem states that after rotating the magnet, the torque acting on it becomes one-fourth of the initial torque: \[ \tau_2 = \frac{1}{4} \tau_1 = \frac{1}{4} mB \] 4. **Setting Up the Equation for the New Torque**: - After rotation, let the new angle be θ. Thus, we can express the new torque as: \[ \tau_2 = m \cdot B \cdot \sin(\theta) \] - Setting this equal to the expression for \(\tau_2\) we derived: \[ m \cdot B \cdot \sin(\theta) = \frac{1}{4} mB \] 5. **Simplifying the Equation**: - We can cancel \(mB\) from both sides (assuming \(mB \neq 0\)): \[ \sin(\theta) = \frac{1}{4} \] 6. **Finding the Angle θ**: - To find θ, we take the inverse sine: \[ \theta = \sin^{-1}\left(\frac{1}{4}\right) \] 7. **Calculating the Angle of Rotation**: - The angle of rotation from the original position (90°) is: \[ \text{Angle of rotation} = 90° - \sin^{-1}\left(\frac{1}{4}\right) \] 8. **Final Calculation**: - Using a calculator, we find: \[ \sin^{-1}\left(\frac{1}{4}\right) \approx 15° \] - Therefore, the angle of rotation is: \[ 90° - 15° = 75° \] ### Final Answer: The angle of rotation is **75 degrees**.
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