In a common emitter transistor amplifier, `beta=60, R_(0)=5000Omega` and internal resistance of a transistor is `500Omega`. The voltage amplification of the amplifier will be

Options

A. 500
B. 460
C. 600
D. 560

Answer

To find the voltage amplification of a common emitter transistor amplifier, we can follow these steps:

### Step 1: Understand the parameters given
- **Beta (β)**: This is the current gain of the transistor, given as 60.
- **Output Resistance (R₀)**: This is given as 5000 ohms.
- **Internal Resistance (Rᵢ)**: This is given as 500 ohms.

### Step 2: Calculate the Resistance Gain
The resistance gain (R_gain) can be calculated using the formula:
\[ R_{\text{gain}} = \frac{R_0}{R_i} \]
Substituting the values:
\[ R_{\text{gain}} = \frac{5000 \, \Omega}{500 \, \Omega} = 10 \]

### Step 3: Calculate the Voltage Amplification
The voltage amplification (A_v) can be calculated using the formula:
\[ A_v = \beta \times R_{\text{gain}} \]
Substituting the values:
\[ A_v = 60 \times 10 = 600 \]

### Step 4: Conclusion
The voltage amplification of the amplifier is 600.

### Final Answer
The voltage amplification of the common emitter transistor amplifier is **600**.

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