Home
Class 12
CHEMISTRY
An aqueous solution is 1.00 molalin KI. ...

An aqueous solution is 1.00 molalin KI. Which change will cause the vapour pressure of the solution to increase ?

A

addition of water

B

addition of `NaCl`

C

addition of `Na_(2)SO_(4)`

D

addition of 100 molal Kl

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

The osmotic pressure of a solution increases if

If common salt is dissolved in water, the vapour pressure of the solution will

To aqueous solution of Nal increasing amounts of solid HgI_2 is added. The vapor pressure of the solution

Which solution will show the maximum vapour pressure at 300K

A system of greater disorder of molecules is more probable. The disorder of molecules is reflected by the entropy of the system. A liquid vapourizes to form a more disordered gas. When a solute is present, there is additional contribution to the entropy of the liquid due to increased randomness. As the entropy of solution is higher than that of pure liquid, there is weaker tendency to form the gas. Thus, a solute (non-volatile) lowers the vapour pressure of a liquid, and hence a higher boiling point of the solution. Similarly, the greater randomness of the solution opposes the tendercy to freeze. In consequence, a lower temperature must be reached for achieving the equilibrium between the solid (frozen solvent) and the solution. The elevation in boiling point (DeltaT_(b)) and depression in freezing point (DeltaT_(f)) of a solution are the colligative properties which depend only on the concentration of particles of the solute and not their identity. For dilute solutions, (DeltaT_(b)) and (DeltaT_(f)) are proportional to the molarity of the solute in the solution. To aqueous solution of Nal , increasing amounts of solid Hgl_(2) is added. The vapour pressure of the solution

Two liquids A and B form an ideal solution. At 300 K , the vapour pressure of a solution containing 1 mol of A and 3 mol fo B is 550 mm Hg . At the same temperature, if 1 mol more of B is added to this solution, the vapour pressure of the solution increases by 10 mm Hg . Determine the vapour pressure of A and B in their pure states.

The vapour pressure of a dilute solution of a solute is influeneced by:

Assuming very dilute aqueous solution of urea, calculate the vapour pressure of solution ( in mm of Hg ) of 0.1 moles of urea in 180 grams of water at 25^(@)C in ( The vapour pressure of water at 25^(@)C is 24 mm Hg )

The vapour pressure of benzene and toluene are 150 mm and 50 mm respectively. A solution is prepared by mixing equal weights of benzene and toluene. Assuming the solution to be ideal, calculate the vapour pressure of the solution.

Two liquid X and Y form an ideal solution. At 300K vapour pressure of the solution containing 1 mol of X and 3 mol of Y 550 mm Hg. At the same temperature, if 1 mol of Y is further added to this solution, vapour pressure of the solution increases by 10 mm Hg. Vapour pressure (in mmHg) of X and Y in their pure states will be , respectively :