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When two pure pea plants one having roun...

When two pure pea plants one having round seeds and the other having wrinkled seeds are crossed, their offsprings have

A

Large starch grain

B

Small starch grain

C

Intermediate starch grain

D

Large starch grain and intermediate starch grain is equal proportion

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The correct Answer is:
To solve the question about the offspring of two pure pea plants, one with round seeds and the other with wrinkled seeds, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Traits**: - Round seeds are represented by the dominant allele (B). - Wrinkled seeds are represented by the recessive allele (b). 2. **Determine the Genotypes of the Parent Plants**: - The pure plant with round seeds has the genotype BB (homozygous dominant). - The pure plant with wrinkled seeds has the genotype bb (homozygous recessive). 3. **Cross the Parent Plants**: - When we cross these two plants (BB x bb), we can determine the gametes produced by each parent. - The gametes from the round seed plant (BB) will only produce B gametes. - The gametes from the wrinkled seed plant (bb) will only produce b gametes. 4. **Determine the Genotypes of the Offspring**: - The offspring will inherit one allele from each parent. Thus, all offspring will have the genotype Bb (heterozygous). 5. **Phenotypic Expression**: - According to Mendel's law, the dominant trait (round seeds) will express itself in the phenotype. However, in this case, we are dealing with a situation of incomplete dominance. - Incomplete dominance means that the heterozygous phenotype (Bb) will express an intermediate trait rather than fully expressing the dominant trait. 6. **Conclusion**: - Therefore, all the offspring will exhibit an intermediate phenotype, which in this case corresponds to intermediate starch grains. ### Final Answer: The offspring will have intermediate starch grains. ---
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