Reaction of cyclohexanone with dimethylamine in the presence of catalytic amount of an acid forms a compound if water during the reaction is continously removed. The compound formed is generally known as

Options

A. a Sciff's base
B. an immine
C. an amine
D. an enamine

Answer

To solve the question regarding the reaction of cyclohexanone with dimethylamine in the presence of an acid, we will follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in this reaction are cyclohexanone (a ketone) and dimethylamine (a secondary amine).

2. **Understand the Reaction Conditions**:
- The reaction occurs in the presence of a catalytic amount of acid. The acid serves to protonate the carbonyl oxygen of cyclohexanone, making it more electrophilic.

3. **Formation of the Intermediate**:
- When cyclohexanone reacts with dimethylamine, the nitrogen of dimethylamine attacks the electrophilic carbon of the carbonyl group, leading to the formation of a tetrahedral intermediate.

4. **Dehydration**:
- As water is continuously removed from the reaction mixture, the tetrahedral intermediate loses a water molecule (dehydration), resulting in the formation of an imine.

5. **Final Product**:
- The product formed is an imine, which is characterized by the presence of a carbon-nitrogen double bond (C=N). In this case, the compound formed is known as a **N,N-dimethylcyclohexanone imine**.

### Conclusion:
The compound formed from the reaction of cyclohexanone with dimethylamine in the presence of acid, with continuous removal of water, is generally known as an **imine**.