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0.1mol of RNH(2)(K(b) = 5 xx 10^(-4)) is...

`0.1mol` of `RNH_(2)(K_(b) = 5 xx 10^(-4))` is mixed with `0.08mol` of `HC1` and diluted to `1L`. Calculate the `[H^(o+)]` in the solution.

A

`8xx10^(-2)`

B

`2xx10^(-11)`

C

`1.23xx10^(-4)`

D

`8xx10^(-11)`

Text Solution

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The correct Answer is:
D
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