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Which of the following configuration of ...

Which of the following configuration of ions has zero CFSE in both strong and weak ligand fields ?

A

`d^(10)`

B

`d^(8)`

C

`d^(6)`

D

`d^(4)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question of which ion configuration has zero Crystal Field Stabilization Energy (CFSE) in both strong and weak ligand fields, we can follow these steps: ### Step 1: Understand CFSE Crystal Field Stabilization Energy (CFSE) is the energy gained when electrons occupy the lower energy d orbitals (t2g) over the higher energy d orbitals (eg) in the presence of ligands. The CFSE can be calculated based on the number of electrons in these orbitals. ### Step 2: Identify the Electron Configurations The question provides four configurations: 1. D10 2. D8 3. D6 4. D4 ### Step 3: Analyze D10 Configuration - In a D10 configuration, all five d orbitals are fully occupied (2 electrons in each orbital). - When ligands approach, the d orbitals split into two sets: t2g (lower energy) and eg (higher energy). - Since all orbitals are filled, there is no pairing of electrons, and thus, the CFSE is zero. ### Step 4: Analyze D8 Configuration - In a D8 configuration, there are 8 electrons. - The filling would typically lead to some electrons occupying the eg orbitals, which would result in a CFSE. - The calculation for CFSE in D8 would show a non-zero value, indicating stabilization but not zero. ### Step 5: Analyze D6 Configuration - In a D6 configuration, electrons can occupy both t2g and eg orbitals depending on whether the field is strong or weak. - This configuration can lead to either high-spin or low-spin arrangements, resulting in non-zero CFSE. ### Step 6: Analyze D4 Configuration - Similarly, in a D4 configuration, the electrons can also occupy both sets of orbitals, leading to non-zero CFSE. ### Step 7: Conclusion From the analysis, only the D10 configuration has zero CFSE in both strong and weak ligand fields. The other configurations (D8, D6, and D4) result in non-zero CFSE due to the presence of unpaired electrons and the need for pairing in certain cases. ### Final Answer The correct answer is **D10 configuration**. ---
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