The polarity of the covalent bond among the following is maximum in

Options

A. F - F
B. O - F
C. N - F
D. C - F

Answer

To determine which covalent bond has the maximum polarity among the given options, we need to analyze the electronegativity values of the atoms involved in each bond. The polarity of a covalent bond is directly proportional to the difference in electronegativity between the two atoms.

### Step-by-Step Solution:

1. **Understand Polarity**: Polarity in a covalent bond arises due to the difference in electronegativity between the two atoms. The greater the difference, the more polar the bond.

2. **Identify the Bonds**: The question provides several options (A, B, C, D) with different pairs of atoms. We need to analyze each pair.

3. **Calculate Electronegativity Differences**:
- **Option A: Fluorine-Fluorine (F-F)**
- Electronegativity of F = 4.0
- Difference = 4.0 - 4.0 = 0
- This bond is non-polar (polarity = 0).

- **Option B: Oxygen-Fluorine (O-F)**
- Electronegativity of O = 3.0
- Electronegativity of F = 4.0
- Difference = 4.0 - 3.0 = 1.0
- This bond has a polarity of 1.

- **Option C: Nitrogen-Fluorine (N-F)**
- Electronegativity of N = 3.0
- Electronegativity of F = 4.0
- Difference = 4.0 - 3.0 = 1.0
- This bond also has a polarity of 1.

- **Option D: Carbon-Fluorine (C-F)**
- Electronegativity of C = 2.55
- Electronegativity of F = 4.0
- Difference = 4.0 - 2.55 = 1.45
- This bond has a polarity of 1.45.

4. **Compare the Polarity Values**:
- F-F: 0
- O-F: 1
- N-F: 1
- C-F: 1.45

5. **Determine the Maximum Polarity**: The bond with the highest polarity is the Carbon-Fluorine bond (C-F) with a polarity value of 1.45.

6. **Conclusion**: Therefore, the covalent bond with the maximum polarity among the given options is the Carbon-Fluorine (C-F) bond.

### Final Answer:
**The polarity of the covalent bond is maximum in option D: Carbon-Fluorine (C-F).**