In a step-up transformer the voltage in the primary is `220 V` and the currrent is `5A`. The secondary voltage is found to be `22000V`. The current in the secondary (neglect losses)is

Options

A. `5A`
B. 50 A
C. 500 A
D. `0.05A`

Answer

To solve the problem of finding the current in the secondary of a step-up transformer, we can follow these steps:

### Step 1: Understand the transformer relationship
In a transformer, the relationship between the primary and secondary voltages and currents is given by the formula:
\[ \frac{V_p}{V_s} = \frac{I_s}{I_p} \]
where:
- \( V_p \) = primary voltage
- \( V_s \) = secondary voltage
- \( I_p \) = primary current
- \( I_s \) = secondary current

### Step 2: Identify the given values
From the problem, we have:
- \( V_p = 220 \, V \)
- \( I_p = 5 \, A \)
- \( V_s = 22000 \, V \)

### Step 3: Rearrange the formula to find the secondary current
We need to find \( I_s \). Rearranging the transformer relationship gives us:
\[ I_s = I_p \cdot \frac{V_p}{V_s} \]

### Step 4: Substitute the known values
Now we can substitute the values into the formula:
\[ I_s = 5 \, A \cdot \frac{220 \, V}{22000 \, V} \]

### Step 5: Calculate the secondary current
Calculating the right-hand side:
\[ I_s = 5 \cdot \frac{220}{22000} \]
\[ I_s = 5 \cdot \frac{1}{100} = 5 \cdot 0.01 = 0.05 \, A \]

### Final Answer
The current in the secondary is:
\[ I_s = 0.05 \, A \]