An element forms an oxide, in which the oxygen is `20%` of the oxide by weight, the equivalent weight of the given element will be

Options

A. 14
B. 32
C. 2
D. 54

Answer

To find the equivalent weight of the element that forms an oxide with 20% oxygen by weight, we can follow these steps:

### Step 1: Determine the weight percentage of the element in the oxide
Given that oxygen is 20% of the oxide by weight, we can find the percentage of the element in the oxide. Since the total weight must equal 100%, the weight percentage of the element will be:

\[ \text{Weight percentage of the element} = 100\% - \text{Weight percentage of oxygen} = 100\% - 20\% = 80\% \]

### Step 2: Set up the relationship for equivalent weight
The equivalent weight (EW) of the element can be calculated using the formula:

\[ \text{Equivalent Weight (EW)} = \frac{\text{Molar Mass of the Element}}{n} \]

Where \( n \) is the number of moles of oxygen that combine with one mole of the element in the oxide.

### Step 3: Calculate the equivalent weight
From the information given, we know that the weight of oxygen in the oxide is 20% and the weight of the element is 80%.

Let’s assume the total weight of the oxide is 100 grams. Then:
- Weight of oxygen = 20 grams
- Weight of the element = 80 grams

Now, we can find the equivalent weight using the formula:

\[ \text{Equivalent Weight} = \frac{80 \text{ grams}}{20 \text{ grams of oxygen}} \times 8 \text{ (the weight of the element)} \]

Calculating this gives:

\[ \text{Equivalent Weight} = \frac{80}{20} \times 8 = 4 \times 8 = 32 \]

### Conclusion
The equivalent weight of the unknown element is 32 grams.

### Final Answer
The equivalent weight of the given element is **32**.

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