Identify the product 'A ' in the given reaction `2CH_3COOHoverset(MnO)rarrA`

Options

A. `CH_3CH_2CHO`
B. `CH_3-CH_2-OH`
C. `CH_3COCH_3`
D. `CH_3-underset(O)underset(||)C-O-underset(O)underset(||)(C)-CH_3`

Answer

To identify the product 'A' in the reaction `2CH₃COOH + MnO → A`, we will analyze the reaction step by step.

### Step 1: Understand the Reactants
The reactants are two moles of acetic acid (CH₃COOH). Acetic acid is a carboxylic acid, and it has the following structure:

```
O
||
CH₃-C-OH
```

### Step 2: Identify the Oxidizing Agent
Manganese oxide (MnO) is used as an oxidizing agent in this reaction. It can facilitate the oxidation of the acetic acid.

### Step 3: Oxidation Process
When acetic acid is oxidized, it can lose hydrogen atoms and form a ketone. In this case, the oxidation of two moles of acetic acid can lead to the formation of acetone (CH₃COCH₃).

### Step 4: Reaction Mechanism
1. The hydroxyl group (-OH) from one acetic acid molecule and a hydrogen atom (H) from the other acetic acid molecule can combine to form water (H₂O).
2. The remaining parts of the acetic acid molecules can then rearrange to form acetone.

### Step 5: Write the Balanced Reaction
The balanced reaction can be represented as:
```
2 CH₃COOH + MnO → CH₃COCH₃ + CO₂ + H₂O + MnO
```
Here, acetone (CH₃COCH₃) is formed as the main product, along with carbon dioxide (CO₂) and water (H₂O).

### Conclusion
Thus, the product 'A' in the reaction is acetone (CH₃COCH₃).

### Final Answer
The product 'A' is acetone (CH₃COCH₃).

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